Tuesday, September 27, 2011

Challenge yourself Question 3 (Isaac gan)
















Lets D be the distance travelled by Chad when meeting Wei Liang and x be the time Chad and Wei Liang met
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X-700*6km/h

730-700=0.5h <=============How much earlier did Chad begin before Wei Liang

1/2*6km/h=3km <====Distance travelled b chad before WL begun.

3km/h+6km/h=9km/h <======Total Speed travelled by WL and C

12-3=9km<=====Distance travelled by Wei Liang and Chad together

9km/9km/h<========Time taken for WL to meet Chad

x=1h+0.5h=1.5h

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