Tuesday, September 27, 2011

Challenge yourself Question 3 (Isaac gan)

Lets D be the distance travelled by Chad when meeting Wei Liang and x be the time Chad and Wei Liang met

730-700=0.5h <=============How much earlier did Chad begin before Wei Liang

1/2*6km/h=3km <====Distance travelled b chad before WL begun.

3km/h+6km/h=9km/h <======Total Speed travelled by WL and C

12-3=9km<=====Distance travelled by Wei Liang and Chad together

9km/9km/h<========Time taken for WL to meet Chad


No comments:

Post a Comment