Wednesday, July 13, 2011

(Viva Voce) Chap 9 Exercise 9 Question 4

http://www.youtube.com/watch?v=9-bKxcpz1gI



Question 4:
Alcohol and water are mixed in the ratio 1:4 by volume. If the volume of the solution is 600cm^3
(a) Find the volume of alcohol in the solution
(b) Find the volume of water in the solution
(c) how much alcohol must be added to the solution so that the ratio of alcohol to water in the solution becomes 1:3 by volume?

A)
Total units from the ratio
1 + 4 = 5

Volume of alcohol->600 ÷ 5 =120cm^3

B)

Volume of water-> 600 ÷ 5 x 4=480cm^3


C)
3 unit -> 480cm^3

1 unit -> 480 ÷ 3 =160cm^3


Difference between the old volume of alcohol and the new volume of alcohol -> 160 - 120=40cm^3

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